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-5x^2-9x+12=0
a = -5; b = -9; c = +12;
Δ = b2-4ac
Δ = -92-4·(-5)·12
Δ = 321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{321}}{2*-5}=\frac{9-\sqrt{321}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{321}}{2*-5}=\frac{9+\sqrt{321}}{-10} $
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